Find the cell potential for a system whose ∆g = +55 kj and 3 moles of electrons are exchanged.

- cell potential = -0.19 volts

Solution:- The equation that shows the connection between and cell potential, E is written  as:

in this equation, n stands for moles of electrons, E stands for cell potential and F stands for faraday constant and it's value is .

It asks to calculate the value of E, so let's rearrange the equation:

Let's plug in the values in it:

since,

Where C stands for coulombs and V stands for volts.

So,

E = -0.19 V

So, the cell potential is -0.19 volts.

altitude, density, pressure

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a gas, having a molecular weight of 13 kg/kmol and a kinematic viscosity of 0.25 cm2/s, flows through a pipe 0.25 m internal diameter and 5 km long at the rate of 0.4 m3/s and is delivered at atmospheric pressure.