I’m trying to find the molarity of h2so4 in this calculation. i attempted it but i still need someone to check my work. i used 10.00 ml of h2so4 and the volume added to it was 24.97 ml of the 0.0924m naoh solution. the equation is 2naoh + h2so4 -> 2h2o + na2so4, so i’m aware 1 mol of h2so4 is 2 mol naoh. what i tried: 0.0924 mol/l x 0.02497 l= 0.002307 mol naoh x 1 mol h2so4/2 mol naoh= 0.001156 mol h2so4 0.0011536 mol h2so4/0.01000 l h2so4= 0.1154m h2so4 am i doing this right?

For cyclohexane compounds drawn in a chair conformation:   -axial bonds are vertical  -equatorial bonds are parallel to two bonds within the ring.  thus, as i assume the chair conformation is drawn:   -the x group is in an axial position, as are the five other vertical bonds.  -three axial bonds are on the top face of the ring  -the other three axial bonds are on the bottom face  the position of the second substituent on each ring carbon is equatorial.  gauche groups must be on an adjacent carbon such as carbon 6 and carbon 2, and also gauche groups are rotated by 60 degrees relative to each other.  drawing the newman projections for c1–c2 and c1–c6 aids in visualizing the groups that are gauche to the y group on c1.  click this link and watch some academic videos that may you more understand the topic