The electron configuration of an element is 1s22s22p63s1. describe what most likely happens when an atom of this element comes near an atom having seven valence electrons.

What is likely  to happens  when an atom  of   with 1s2 2s2 2p6 3s1  electron configuration  comes near an  atom  having  seven valence electrons  is  that

   An  ionic   bond   will  be formed between    element  with   electronic  configuration of 1s2 2s2 2p6 3s1    and  atom  with seven  valence electrons.

 Explanation

 Ionic bond  is  formed when  one atom  loses  valence electron  while  the  other  atom    gain electron to  fill  the valence electron.

Atom with  1s2 2s2 2p6 3s1  electron configuration  loses   one electron    while  atom  having  seven valence  electrons gain  one electron  to  fill its  valence  electrons that is  obtain  octet  electron configuration.

Explanation:

According to the octet rule, there must be 2, 8, 18, 32 and so on number of electrons present in K, L, M, N and so on shells.

Since, there is there is 1 valence electron present in the valence shell of given electronic configuration as there are 2, 8, 1 electrons. Therefore, it will donate its one extra electron to another atom.

For example, an atom with 7 valence electrons will most likely take up this extra electron in order to complete its octet to attain stability.

Hence, an ionic bond will be formed between both the atoms.

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the answer is c

tell me if wrong