Two students made the lewis dot diagrams of nh3. the diagrams are as shown. which student drew the correct lewis dot diagram? only student a only student b both student a and student b neither student a nor student b

Only student B.

Step-by-step explaination: There are five electrons in the valence shell of Nitrogen atom and one electron in the valence shell of Hydrogen atom. So, except two electrons, Nitrogen atom will have to share its three valence electrons with the valence electrons of  three hydrogen atoms. But, in the diagram of Student A, it is shown that Nitrogen is donating three electrons to the hydrogen atoms rather than sharing while diagram of Student B indicates sharing.  

So, the diagram of Only Student B shows the correct Lewis dot diagram.

Answer :  The correct option is, Only Student B

Explanation :

Lewis-dot structure : It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule.

In the Lewis-dot structure the valance electrons are shown by 'dot'.

The given molecule is,

As we know that nitrogen has '5' valence electrons and hydrogen has '1' valence electron.

Therefore, the total number of valence electrons in = 5 + 3(1) = 8

According to Lewis-dot structure, there are 6 number of bonding electrons and 2 number of non-bonding electrons.

The Lewis dot structure of student A is wrong because there is a coordinate bond present between the nitrogen and hydrogen is not covalent.

The correct Lewis-dot structure of is shown by the student B.

chemical digestion occurs in the stomach were hcl and pepsin forms chyme, the mouth in which salivary amylase breaks down starch to form bolus, and the small intestine specifically the duodenum.

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o