Consider the reaction: hcl(aq) + naoh(aq) → naoh(aq) + h2o(l) how much 0.113 m naoh solution will completely neutralize 1.25 l of 0.228 m hcl solution? express your answer in liters to three significant figures.

 The amount of NaOH   formed  is   2.522 L

calculation

HCl  +NaOH → NaCl  +H2O

Step 1:find the  moles of HCl  =  molarity x  volume in liters

    =  1.25 l  x  0.228 M   = 0.285 moles

step 2:  use the   mole ratio to  calculate the moles of NaOH

the  mole ratio of NaOH:HCl  = 1:1 therefore the  moles  of NaOH  is also

= 0.285  moles

Step 3:  find the  volume  of  NaOH

volume =  moles /molarity

=  0.285   /0.113  = 2.522 L

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