What volume (in l) of a 4.13m lithium nitrate solution would be needed to make 195ml of a 1.05m solution by dilution?

0.0496 L

Explanation:

You are diluting the LiNO₃ solution, so you can use the dilution formula.

c₁V₁ = c₂V₂                                    Divide each side by c₁

  V₁ = V₂ × c₂/c₁

c₁ = 4.13 mol·L⁻¹; V₁ =?

c₂ = 1.05 mol·L⁻¹; V₂ = 195 mL     Calculate V₁

V₁ = 195 × 1.05/4.13

V₁ = 195 × 0.2542

V₁ = 49.6 mL                                Convert to litres

V₁ = 49.6 × 1/1000

V₁ = 0.0496 L

alkaline metals are lithium, sodium, rubidium, potassium, cesium and francium.

alkali metals have electronegativity from 0.7 to 1, lowest in periodic table of elements, which means that alkali metals (i group in periodic table) has positive oxidation number in compounds.

electronegativity is a chemical property that describes the tendency of an atom to attract a shared pair of electrons towards itself.

alkaline metals (far left in main group) have lowest ionizations energy and easy remove valence electrons,

for example, potassium is the alkali metal and has a single valence electron in the outer electron shell.

electron configuration of potassium is: ₁₉k 1s²2s²2p⁶3s²3p⁶4s¹.

they can not exist alone in nature, because they are very reactive.

periodic trends is an atom that gets larger as the number of electronic shells increase, the radius of atoms increases as you go down a certain group in the periodic table of elements. in general, the size of an atom will decrease as you move from left to right of a certain period.