(03.01 lc) an atom has the following electron configuration. 1s22s22p63s23p4 how many valence electrons does this atom have? 2 4 6 12

The correct answer is 6.

Explanation:

Valence electrons is defined as the electrons which are present in the outermost shell of the element.

For the given electronic configuration:  

The valence shell of the given configuration is '3s' and '3p' where n = 3 (highest).

The number of electrons that 3s and 3p sub-shells contain are (2 + 4) = 6

Hence, the number of valence electrons of the given atom is 6.

the answer is 303.15 or 303

i believe the answer is true.