How many grams are there in 7.4 x 1023 molecules of h2so4?

7.4x10^23 = molecules of silver nitrate sample  

6.022x10^23 number of molecules per mole (Avogadro's number)  

Divide molecules of AgNO3 by # of molecules per mol  

7.4/6.022 = 1.229 mols AgNO3 (Sig Figs would put this at 1.3)  

(I leave off the x10^23 because they both will divide out)  

Use your periodic table to find the molar weight of silver nitrate.  

107.868(Ag) + 14(N) + 3(16[O]) = 169.868g/mol AgNO3  

Now multiply your moles of AgNO3 with your molar weight of AgNO3  

1.229mol x 169.868g/mol = 208.767g AgNO3

i think it is d. e because the next one is igneous.

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