Given the naoh density =1.0698g ml^-1, how many ml of .71m hcl would be required to neutralize 11.33g of 2.03 m naoh?

 The volume in ml of 0.71 M HCl  that would  be  required to neutralize  11.33 g   of 2.03 M NaOH  is 30.3 ml

calculation

Step 1 : write equation  for reaction

NaOH + HCl →NaCl +H₂O

Step 2:find the volume of NaOH

volume=mass/ density

= 11.33 g/ 1.0698 g/ml  =10.59 ml

Step 3: find the  moles of NaOH

moles  = molarity  x volume  in liters

molarity= 2.03 M=2.03 mol/l

volume  in liters =10.59/1000 =0.0106 L

moles  = 2.03 M  x 0.0106 L =0.0215  moles

step 4:  use the mole ratio to determine the moles of HCl

from  equation in step 1 , NaOH:HCl  is 1:1 therefore the moles of HCl is also 0.0215  moles

Step 5: find volume of  HCl

volume= moles/ molarity

molarity  =0.71 M =0.71 mol/l

=0.0215 moles /0.71  mol/l=0.0303 L

into ml =0.0303 x 1000=30.3 ml

both adhesion and cohesion are attractions.

they are different in that adhesion is the force of attraction between the molecules of two different substances, whereas cohesion is the force of attraction between molecules of the same substance.

possible examples include capillary action, in which the adhesion between water and glass causes the water to rise in a narrow tube against the force of gravity.

because of hydrogen bonding, water is extremely cohesive.

this causes molecules on the surface of water to be drawn inward, which is why drops of water form beads on smooth surfaces.

hope this .

cytokinesis is the splitting of a cell membrane to form 2 identical daughter cells. it's similar to mitosis as both cells have identical copies of dna and cytokinesis is a step in the mitotic cycle.