Use standard enthalpies of formation to calculate the change in enthalpy for dry ice sublimation. (the î´hâf for co2(s) is - 427.4kj/mol).

The change in enthalpy for dry ice sublimation is 33.9 kJ.

Let's consider the equation for the sublimation of dry ice.

CO₂(s) ⇄ CO₂(g)

Given the standard enthalpies of formation (ΔH°f), we can calculate the standard enthalpy change of sublimation (ΔH°s) using the following expression.

where,

The change in enthalpy for dry ice sublimation is 33.9 kJ.

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We need to know the change in enthalpy for dry ice sublimation.

Change in enthalpy for dry ice sublimation is: + 427.4 KJ/mol

The enthalpy of dry ice sublimation is the energy required to melt one mole of dry ice into liquid.

Enthalpy of formation is opposite of enthalpy of sublimation.

Given, enthalpies of formation is -427.4 KJ/mol, so, enthalpy of sublimation= +427.4 KJ/mol.

a boiling water reactor does not boil the water. a pressurized water reactor boils the water faster. a pressurized water reactor is heated directly by the core. a pressurized water reactor does not use fission.