If a weaker solution of sodium bicarbonate was used in beaker b, would that solution require more or less acetic acid to neutralize it? why?

Answer is: less acetic acid to neutralize it.

Balanced chemical reaction of sodium bicarbonate solution and acetic acid: NaHCO₃(aq) + CH₃COOH(aq) → CH₃COONa(aq) + H₂O(l) + CO₂(g).

According to chemical reaction: n(NaHCO₃) : n(CH₃COOH) = 1 : 1.

Stronger solution of sodium bicarbonate (NaHCO₃), more acetic acid (CH₃COOH) is neeed for neutralization.

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percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally