When a metal was exposed to photons at a frequency of 4.08× 1015 s–1, electrons were emitted with a maximum kinetic energy of 5.30× 10–19 j. calculate the work function of this metal. also, what is the maximum number of electrons that could be ejected from this metal by a burst of photons (at some other frequency) with a total energy of 6.36× 10–7 j? i would love an explanation if that is possible!

Answer :

The work function of this metal is,

The maximum number of electrons released =

Solution : Given,

Frequency =

Kinetic energy =

Total energy =

First we have to calculate the work function of the metal.

Formula used :

where,

K.E = kinetic energy

h = Planck's constant =

= frequency

w = work function

Now put all the given values in this formula, we get the work function of the metal.

By rearranging the terms, we get

Therefore, the works function of the metal is,

Now we have to calculate the maximum number of electrons released.

The maximum number of electrons released =

The maximum number of electrons released =

Therefore, the maximum number of electrons released =

- calcium has greater affinity to bond with electron receptors than hydrogen does and hence, it has the ability to replace hydrogen in most of its compounds.

- lithium has 2 valence electrons in the product because it can make only 1 bond with hydrogen. beryllium has 4 valence electrons in the product because it can only make 2 bonds. it has fewer electrons than neon and can react with electron donors. each hydrogen has 2 valence electrons, the same as helium.

- the covalent bond formed between carbon and hydrogen is polar because carbon is more electronegative than hydrogen and it attracts the bonded electron pair closer to itself, thus giving hydrogen a partial positive charge.

- a hydrogen bond is a relatively weak bond that hydrogen atoms make with the electronegative atoms nitrogen, oxygen or fluorine.

so the best choice is a.) 2 calcium (ca) atoms

i dont know the answe