What is the change in the boiling point of a solution made by dissolving 14.7 g of c6h12o6 into of water? the density of water is and ?

First determine the molality of the solution. m = (w solute)/[(mm solute)(kg solvent)] -- mm means molar mass. So,

m = (14.7 g)/[(180 g/mol)(0.150 kg) =0.544 mol/kg = 0.544 m

Change in boiling point (∆t) = m x Kbp = (0.544 m)(0.512 °C/m) = 0.28°C

The solution will boil at 100.28°C at 1 atm.

the density if water is 1.00 g/ml and Kb= 0.512 C/m

i believe the answer is three water molecules