What is the number of each type of atom on the right side of the equation 2na3po4(aq)+2cocl2(aq)→2co3(po4)2(s )+6nacl(aq)

Answer : The number of atoms are, 6, 4, 16, 6, 6

Explanation :

The given balanced chemical reaction is:

This reaction is balanced reaction because in this reaction all the atoms of individual elements are completely balanced.

From the balanced reaction we conclude that and are present on the right side of the equation.

Number of atoms of cobalt (Co) present on right-side of the equation = 6

Number of atoms of phosphorous (P) present on right side of the equation = 4

Number of atoms of oxygen (O) present on right side of the equation = 16

Number of atoms of sodium (Na) present on right side of the equation = 6

Number of atoms of chlorine (Cl) present on right side of the equation = 6

Hence, the number of atoms are, 6, 4, 16, 6, 6