Astudent needs to prepare 50.0 ml of a 1.20 m aqueous h2o2 solution. calculate the volume of 4.9 m h2o2 stock solution that should be used to prepare the solution.

Answer : The volume of 4.9 M stock solution used to prepare the solution is, 12.24 ml

Solution : Given,

Molarity of aqueous solution = 1.20 M = 1.20 mole/L

Volume of aqueous solution = 50.0 ml = 0.05 L

(1 L = 1000 ml)

Molarity of stock solution = 4.9 M = 4.9 mole/L

Formula used :

where,

= Molarity of aqueous solution

= Molarity of stock solution

= Volume of aqueous solution

= Volume of stock solution

Now put all the given values in this formula, we get the volume of stock solution.

By rearranging the term, we get

Therefore, the volume of 4.9 M stock solution used to prepare the solution is, 12.24 ml

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explanation:

the density of gold = 19.3 g/cm3

the relation between density and mass and volume is

density = mass / volume

given :

mass of gold = 13 g

density = 13g / volume = 19.3

volume = 13 /19.3 = 0.67 cm^3

thus volume of gold nugget = 0.67 cm^3