Whats the specific heat of an unknown substance if the addition of 800 joules of heat energy caused a 30 gram sample to warm from 20 to 40 degrees celsius?

 The specific heat capacity of unknown  substance  is 1.333 g/j/°c

  calculation

 Specific heat capacity is calculated using  Q= MCΔT  formula

where;

Q(heat)= 800 j

M(mass) = 30 g

C(specific heat  capacity) =?

ΔT( change in temperature)  = 40°c - 20°c = 20°c

make C  the subject of the formula  by diving both side of the formula by MΔT

C  is therefore = Q/MΔT

800j / 30 g x  20°c = 1.333 j/g/°c

air quality

poor drinking water

and heavy polution

can lead to poor health

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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