Asample of ideal gas at room temperature occupies a volume of 12.0 l at a pressure of 802 torr . if the pressure changes to 4010 torr , with no change in the temperature or moles of gas, what is the new volume, v 2 ?

 The new  volume  is  2.4 L

calculation

The new volume is calculated using Boyle's  law formula

That  is  P₁V₁=P₂V₂

where,

p₁ =  802 torr

V₁ = 12.0 l

P₂ = 4010 torr

V₂=?

make  V₂ the subject of the formula  by diving  both side of equation by P₂

V₂ = P₁V₁/P₂

V₂  is therefore = {(12.0 l × 802 torr) 4010 torr}  = 2.4 L

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