Tim wants to store 0.122 moles of helium gas at 203 kpa and 401 k. which is the volume of the helium gas needed for storage? a.0.240 l b.0.510 l c.2.00 l d.3.37 l

 The  volume  of Helium gas needed for storage  is 2.00 L (answer C)

  calculation

 The volume of Helium is calculated using ideal gas equation

That is Pv =nRT

where;

 P( pressure) = 203 KPa

V(volume)=?

n(number  of moles) =  0.122 moles

R(gas constant) = 8.314  L.Kpa/mol.K

T(temperature)= 401 K

make V the  subject of the formula  by diving both side  by P

V=nRT/p

V={[0.122  moles x 8.314 L. KPa/mol.K  x 401 K]  / 203 KPa} = 2.00 L

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