What is the molarity of a saline solution that contains 0.900 g nacl (58.44 g/mol) dissolved in 100.0 ml of solution?

  The molarity  of a saline solution  that contain 0.900 g NaCl (58.44 g/mol) dissolved in 100.0 ml solution is  0.15 M

  calculation

 Molarity = moles /volume  in liters

volume in  liters = 100.0 ml / 1000 = 0.1 L

 moles =  mass÷ molar mass

=  0.900 g ÷58.44 g/mol =0.015 moles

molarity  is therefore =   0.015 moles /  0.1 L =0.15 M

2b2t

explanation:

2b2t

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.