How many grams of carbon monoxide are needed to react with an excess of iron (iii) oxide to produce 198.5 grams of iron? fe2o3(s) + 3co(g) --> 3co2(g) + 2fe(s) show work so i can understand the concept

The grams  of   carbon monoxide  is 148. 68 g

calculation

Fe₂O₃(s)  + 3CO (g) →   3 CO₂(g)  + 2Fe (s)

 Step 1: find  the moles  of  CO

   moles = mass÷ molar mass

 from periodic table the  molar mass of Fe =56 g/mol

 moles =  198.5 g÷ 56 g/mol =3.54  moles

Step 2 : use the mole ratio to determine the  moles of  Co

 from given equation  Co: Fe is 3: 2

therefore the  moles of CO = 3.54 moles  x 3/2= 5.31 moles

Step 3 Find mass of Co

mass  =  moles × molar mass

from periodic table the  molar mass of CO = 12+ 16 = 28 g/mol

= 5.31  moles × 28 g/mol = 148.68  g

the answer is definitely c.

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.