Chemistry, 28.06.2019 18:00 holycow7868

Rank the following compounds in order of decreasing boiling point: sodium bromide (nabr), carbon tetrafluoride (cf4), and chloroform (chcl3) rank from highest to lowest boiling point. to rank items as equivalent, overlap them.

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Answer from: terrickaimani

Highest to lowest boiling point is

NaBr > CHCl3 > CF4

NaBr - ionic

CHCl3 - dipole - dipole

CF4 - dispersion force

If Intermolecular forces are strong then the molecule will have greater boiling point as it requires more energy to break the bond between molecules and convert them from liquid to gas.

As NaBr is an ionic compound(Na is a metal and Br is non metal).

Hence it has the strongest intermoleuclar force of attraction and it will have the highest boiling point.

CHCl3 and CF4 are covalent compounds.

But CHCl3 is polar covalent compound hence it has higher boiling point than CF4.

CF4 is non polar covalent compound [due to the regular or symmetrical structure of CF4,where C-F bond is polar but the CF4 molecule as a whole is not polar as the polarity cancels out due to equal pulling of electrons by F towards all sides]

Answer from: Quest

Organisms are more likely to be more preserved in mud than sand because mud is moist and wet, while sand is very dry.

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

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Rank the following compounds in order of decreasing boiling point: sodium bromide (nabr), carbon te...

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