When 25.0 grams of water are cooled from 20.0 degrees celsius to 10.0 degrees celsius the number of joules of heat energy released is?

The amount of heat released is -1046 J

Explanation:

To calculate the amount of heat released, we use the equation:

where,

q = heat released = ?

m = mass of water = 25.0 g

c = specific heat capacity of water = 4.184 J/g.°C

= change in temperature =

Putting values in above equation, we get:

Hence, the amount of heat released is -1046 J

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