In the equation 2k+ 2h2o > 2koh +h2how much hydrogen is produced of only .04 mol of potassium is used? a. 01 mol of h2b. 02 mol of h2c. 03 mol h2d. 04 mol of h2 and explain the answer

 The much hydrogen that is  produced   is 0.02 mol  of H₂ (answer  B)

 Explanation

2K +2H₂O→ 2 KOH + H₂

 Use the mole ratio to determine the moles of H₂

 From equation above the  K :H₂  is  2:1

Therefore the moles of H₂ = 0.04 x 1/2 = 0.02  mol  of H₂

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

quartz

explanation: