How many molecules of isopently acetate c7h1402 are released (1x10^ -6g) in a typical bee sting

The  number of molecules of isopently acetate is  4.63  x 10¹⁵  molecules

 calculation

Step 1:  find the moles of isopently acetate( C₇H₁₄O₂)

moles  =  mass÷  molar mass

From periodic table the molar mass of C₇H₁₄O₂

= (12 x7 ) + (1 x14) +(16 x2) =130 g/mol

moles = 1 x10⁻⁶ g÷ 130 g/mol =  7  x 10⁻⁹ moles

step 2 ; use the Avogadro's  law  constant to calculate the number of molecules

That  is according to Avogadro's law  1 mole  = 6.02 x 10²³  molecules

                                                          7 x 10⁻⁹ moles = ?  molecules

by cross multiplication

= { (7 x 10⁻⁹ moles x  6.02 x10²³  molecules) / 1  mole} = 4.63 x 10¹⁵  molecules

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