What is the percent composition of nahco3?

Na = 27.37%, H = 1.20%, C = 14.30% and O = 57.14%

Explanation:

took the test

- Na = 27.37%, H = 1.20%, C = 14.30% and O = 57.14%

Solution:- For the percentage composition of a compound, the atomic mass of each atoms times its subscript is divided by the molar mass of the compound and multiplied by 100.

The given compound is .

mass of Na = 22.99 g

mass of H = 1.008 g

mass of C = 12.01 g

mass of O = 3(16) = 48 g

Molar mass of compound = 22.99 g + 1.008 g + 12.01 g + 48 g = 84.008 g

percentage of Na =

= 27.37%

percentage of H =

= 1.20%

percentage of C =

= 14.30%

percentage of O =

= 57.14%

the correct answer is a

- calcium has greater affinity to bond with electron receptors than hydrogen does and hence, it has the ability to replace hydrogen in most of its compounds.

- lithium has 2 valence electrons in the product because it can make only 1 bond with hydrogen. beryllium has 4 valence electrons in the product because it can only make 2 bonds. it has fewer electrons than neon and can react with electron donors. each hydrogen has 2 valence electrons, the same as helium.

- the covalent bond formed between carbon and hydrogen is polar because carbon is more electronegative than hydrogen and it attracts the bonded electron pair closer to itself, thus giving hydrogen a partial positive charge.

- a hydrogen bond is a relatively weak bond that hydrogen atoms make with the electronegative atoms nitrogen, oxygen or fluorine.

so the best choice is a.) 2 calcium (ca) atoms