When 21.3 moles of c3h8 burn in excess oxygen how many moles of co2 will be formed?

63.9moles

Explanation:

Given parameters:

Number of moles of C₃H₈ = 21.3moles

Unknown parameter:

Number of moles of CO₂ produced = ?

Solution

In order to find the number of moles of carbon dioxide produced we must first write the balanced reaction equation.

This reaction is a combustion of hydrocarbon reaction. It usually occurs in the presence of excess oxygen gas and the product is water and carbon dioxide.

The reaction equation is shown below:

        C₃H₈ + 5O₂ → 3CO₂ + 4H₂O

From the equation:

         1 mole of C₃H₈ produced 3 moles of CO₂

Therefore, 21.3 moles of  C₃H₈ will produce (21.3 x 3)moles of CO₂

The number of mole of carbon dioxide produced is 63.9moles

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml