Temperature of 1.4 moles of gas’s with pressure of 3.25 atmosphere in a 4.738-liter container

-139 °C

Step-by-step explanation:

We can use the Ideal Gas Law and solve for T.

pV = nRT     Divide each side by nR

 T = (pV)/(nR)

Data:  

p = 3.25 atm

V = 4.738 L

n = 1.4 mol

R = 0.082 06 L·atm·K⁻¹mol⁻¹

Calculation:

T = (3.25 ×4.738)/(1.4 × 0.082 06)

T =  134 K

T = (134 - 273.15) °C

T = -139 °C

the answer for sodium is 0.186

the answer for rubidium is 0.251

the positions which points up in upward carbon and down in downward carbon are axial

and vice versa holds true for equatorial positions

so the correct answer with labelled diagram will be