Magine a solution of two liquids in which the molecules interact less favorably than they do in the individual liquids. will this solution deviate positively from, deviate negatively from, or ideally follow raoult's law?

The correct answer is that it will deviate positively.

On the basis of Raoult's law, the vapor pressure of the solution is equivalent to the vapor pressure and mole fraction of the solvent at that temperature.  

In the given question, the deviation of molecules in the individual liquid is greater in comparison to the solution of two liquids, which is also illustrated by the fact that cohesive force of the like molecules is more than the adhesive force of the, unlike molecules. This condition allows the solution to escape more readily. Thus, the vapor pressure is more than expected from the Raoult's law and thus results in a positive deviation.