Aballoon’s internal pressure is 1.25 atm, and its volume is 2.50 l. if the balloon is taken to the bottom of the ocean (pressure = 95.0 atm), what would be its new volume? assume that the temperature does not change. (round to the nearest hundredth place) l

Where temperature is constant P1V1 = P2V2   where P = pressure and  V = volume.

so 1.25 * 2.5 = 95 * V2

V2 = (1.25 * 2.5) / 95

= 0.03  L to the nearest hundredth..

0.03 L 

Step-by-step explanation:

Since all other properties constant, we can use Boyle’s Law.

p₁V₁ = p₂V₂    Divide each side by p₂

   V₂ = V₁ × p₁/p₂

Data:

p₁ =     1.25 atm; V₁ = 2.50 L

p₂ = 95.0   atm; V₂ = ?

Calculations:

V₂= 1.25 × (2.50/95.0)

V₂= 1.25 × 0.026 32

V₂ ≈ 0.03 L

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explanation: