What volume of 2m hcl, a common laboratory stock solution, must be used to prepare 150.0 ml of 1m hcl? show work

75.0 mL.

Explanation:

We have a rule says that "the number of millimoles before dilution is the same after dilution".This rule can be expressed as (M1V1)before dilution = (M2V2)after dilution.Before dilution: M1 = 2.0 M & V1 = ??? (The volume needed to be calculated)After dilution: M2 = 1.0 M & V2 = 150.0 mL.Now, the volume must be used from the stock to prepare the desired solution:V1 before dilution = (M2V2)after dilution / (M1) = (1.0 M x 150.0 mL) / (2.0 M) = 75.0 mL.

Answer charle's law

Qand k are only the same when the forward rate of the reaction has reached zero.