Chemistry, 24.06.2019 16:30 kingemzy

Acompound was analyzed and found to contain 13.5 g ca, 10.8 g o, and 0.675 g h. what is the empirical formula of the compound?

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Answer from: germanie123

The empirical formula of the compound is Ca(OH)_2

Explanation:

To find the empirical formula of the compound, we follow following steps:

Step 1: Finding the number of moles of the given elements.

To calculate the number of moles, we use the formula:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

For Calcium:

Molar mass of calcium = 40 g/mol

Given mass of calcium = 13.5 g

Putting values in above equation, we get:

$\text{Number of moles}=\frac{13.5g}{40g/mol}=0.3375$

For Oxygen:

Molar mass of oxygen = 16 g/mol

Given mass of oxygen = 10.8 g

Putting values in above equation, we get:

$\text{Number of moles}=\frac{10.8g}{16g/mol}=0.675$

For Hydrogen:

Molar mass of hydrogen = 1 g/mol

Given mass of hydrogen= 0.675 g

Putting values in above equation, we get:

$\text{Number of moles}=\frac{0.675g}{1g/mol}=0.675$

Step 2: Now, to obtain the mole ratio, we divide the moles of each element by the smallest number of moles calculated.

For Ca = $\frac{0.3375}{0.3375}=1$

For H = $\frac{0.675}{0.3375}=2$

For O = $\frac{0.675}{0.3375}=2$

The ratio of Ca : O : H = 1 : 2 : 2

Step 3: Now, the ratio of the elements is represented as the subscripts in the empirical formula.

The formula becomes: $CaO_2H_2\approx Ca(OH)_2$

Hence, the empirical formula of the compound is Ca(OH)_2

Answer from: Quest

a. hope i'm right

explanation:

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

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Acompound was analyzed and found to contain 13.5 g ca, 10.8 g o, and 0.675 g h. what is the empirica...