Agas at constant volume has a pressure of 2.80 atm at 400. k. what will be the pressure of the gas at 360. k? 2.52 atm 2.94 atm 3.11 atm 3.78 atm

Hello!

A gas at constant volume has a pressure of 2.80 atm at 400. K. What will be the pressure of the gas at 360. K?

We have the following information:

P1 (initial pressure) = 2.80 atm

T1 (initial temperature) = 400 K

P2 (final pressure) = ? (in atm)

T2 (final temperature) = 360 K

According to the Law of Charles and Gay-Lussac in the study of gases, we have an isochoric (or isovolumetric) transformation when its volume remains constant or equal, if the temperature increases, the pressure increases and, if the temperature decreases, the pressure also decreases, they are directly proportional.then we will have the following formula:

multiply the means by the extremes

2.52 atm

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I Hope this helps, greetings ... Dexteright02! =)

is there multiple choice answers?

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j