Asample of seawater contains 78.0 grams of nacl in 2,025 ml of solution. if the molar mass of nacl is 58.443 g/mol, what is the molarity of this sample?

Explanation:

Molarity is defined as number of moles per liter of solution.

Mathematically,        Molarity =

Also, it is known that no. of moles equal mass divided by molar mass. Since, it is given that 2,025 mL equals 2.025 L, mass is 78.0 g, and molar mass is 58.443 g/mol.

Therefore,     No. of moles =

                                            =

                                            = 1.33 mol

Hence, calculate the molarity as follows.

                 Molarity =

                                =

                                = 0.656 mol/L

Thus, we can conclude that molarity of the given sample is 0.656 mol/L.

answer; i do believe the correct answer is (river); /// good luck

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"