Chemistry, 23.06.2019 16:00 emilystartk
Challenge question: this question is worth 6 points. as you saw in problem 9 we can have species bound to a central metal ion. these species are called ligands. in the past we have assumed all the d orbitals in some species are degenerate; however, they often are not. sometimes the ligands bound to a central metal cation can split the d orbitals. that is, some of the d orbitals will be at a lower energy state than others. ligands that have the ability to cause this splitting are called strong field ligands, cnâ’ is an example of these. if this splitting in the d orbitals is great enough electrons will fill low lying orbitals, pairing with other electrons in a given orbital, before filling higher energy orbitals. in question 7 we had fe2+, furthermore we found that there were a certain number (non-zero) of unpaired electrons. consider now fe(cn)6 4â’: here we also have fe2+, but in this case all the electrons are paired, yielding a diamagnetic species. how can you explain this?
Answers: 2
Chemistry, 21.06.2019 14:30
Janel’s class studied properties of matter and how matter can change. janel decided she would do an experiment mixing baking soda and vinegar.question: describe the properties of baking soda and vinegar, and explain the changes that janel should see when she mixes the two types of matter. •first, identify the physical state of matter of baking soda. describe another property of baking soda. •next, identify the physical state of matter of vinegar. describe another property of vinegar. •then, explain what janel should see when she mixes the baking soda and vinegar. •describe the states of matter of the new materials that are formed. •explain how janel can be certain a change has occurred. me
Answers: 3
Chemistry, 22.06.2019 14:30
The three types is stress that act on earths rocks are compression, tension, and
Answers: 1
Chemistry, 22.06.2019 17:30
Air can be considered a mixture. which statement does not explain why?
Answers: 1
Chemistry, 22.06.2019 19:10
Δu of , in kj/kg, as it isto k, (a)as a of , (b) at , (c) at .
Answers: 2
Challenge question: this question is worth 6 points. as you saw in problem 9 we can have species bo...
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