If 125 cal of heat is applied to a 60.0-g piece of copper at 25.0 ? c , what will the final temperature be? the specific heat of copper is 0.0920 cal/(g? ? c) .

Amount of heat = mass x specific heat x change in temperature

125 = 60.0 x 0.0920 x Dt

So Dt = 125 / 5.52

= 22.65

Final temperature = 24 + 22.65 = 46.65 degree C

hope that help

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