How many grams of cupric sulfate pentahydrate are needed to prepare 50.00 ml of 0.0800m cuso4× 5h2o?

Explanation:

Molarity is defined as number of moles per liter of solution.

Mathematically,         molarity =

It is given that molarity is 0.0800 M and volume is 50.00 mL or 0.05 L.

           molarity =

            0.0800 M =

            no. of moles = 1.6 mol

Therefore, molar mass of cupric sulfate pentahydrate is 249.68 g/mol. So, calculate the mass as follows.

                No. of moles =

             mass in grams =

                                       =

                                       = 399.488 g

Thus, we can conclude that 399.488 g of cupric sulfate pentahydrate are needed to prepare 50.00 mL of 0.0800M CuSO4× 5H2O.

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in scientific notation, the value of the  speed of light in a vacuum

  will be written as 2.995 * 10^8. when this value is represented in the form of

  a * 10^b, then, a = 2.995 and b = 8.

the value of the speed of light in a vacuum given above can also be rounded up to approximately 300000000. in this case, the scientific notation will be written as 3 *10^8.