How many grams of magnesium metal will react completely with 8.3 liters of 5.5 m hcl? show all of the work needed to solve this problem. mg (s) + 2hcl (aq) → mgcl2 (aq) + h2 (g)

Ans: around 547 g of Mg will react completely with HCl

Given reaction:

Mg(s) + 2HCl (aq) → MgCl2(aq) + H2(g)

Volume of HCl, V= 8.3 L

Molarity of HCl, M = 5.5 M i.e. 5.5 moles/L

# Moles of HCl = M*V = 5.5 moles/L 8.3 L = 45.65 moles

Based on the reaction stoichiometry 1 mole of Mg reacts with 2 moles of HCl

Therefore moles of Mg that would react completely with 45.7 moles of HCl is:

= 45.65/2 = 22.825 moles

Atomic mass of Mg = 24 g/mole

Mass of Mg = 22.825 moles*24 g/mole = 547.8 g

explanation:

two years ago, when picking flowers in the mountains back of yosemite valley, i found a book. it was blotted and storm-beaten; all of its outer pages were mealy and crumbly. the paper seemed to dissolve like the snow beneath which it had been buried, however; many of the inner pages were well preserved. and although all were more or less stained and torn, whole chapters were easily readable. this is the condition of the great open book of yosemite glaciers today; its granite pages have been torn and blurred by the same storms that wasted the castaway book.

two years ago, when picking flowers in the mountains back of yosemite valley; i found a book. it was blotted and storm-beaten, all of its outer pages were mealy and crumbly. the paper seemed to dissolve like the snow beneath which it had been buried, however, many of the inner pages were well preserved. and although all were more or less stained and torn; whole chapters were easily readable. this is the condition of the great open book of yosemite glaciers today, its granite pages have been torn and blurred by the same storms that wasted the castaway book.