How many joules of heat are absorbed to raise the temperature of 650 grams of water from 5.00c to it's boiling point, 100c

Answer : The amount of heat absorbed are, 258485.5 J

Solution :

Formula used :

where,

Q = heat gained  = ?

m = mass of water = 650 g

c = specific heat of water =      

= final temperature =

= initial temperature =

Now put all the given values in the above formula, we get the final temperature of copper.

Therefore, the amount of heat absorbed are, 258485.5 J

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