Ethylene glycol (molar mass = 62 g/mol)is used as an antifreeze in cars. if 450 g of ethylene glycol is added to 4.25 kg of water, what is the molality? calculate how much the freezing point of water will be lowered. the freezing point depression constant for water is kf = -1.86°c/m. show your work.

Molality is 1.7m and the freezing point of water will be lowered by

Explanation:

Depression in freezing point is given by:

= Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

= freezing point constant =

m= molality  =

Weight of solvent (water) = 4.25 kg  

Molar mass of solute (ethylene glycol) = 62 g/mol

Mass of solute added (ethylene glycol) = 450 g

m= molality  =

Molality of solution will be 1.7m.

The freezing point of water will be lowered by

precipitation

explanation:

when it goes from cloud to rain/back to earth in the form of rain

c)red bank

explanation:

red bank is a borough in monmouth county, new jersey, incorporated in 1908 and located on the navesink river, the area's original transportation route to the ocean and other ports.