Read the given equation. na2o2 + co2 → na2co3 + o2 what volume of o2 gas is produced from 2.80 liters of co2 at stp?

1.40 L  

Step-by-step explanation:

We can use Gay-Lussac's Law of Combining Volumes to solve this problem.

Gases at the same temperature and pressure react in simple whole-number ratios.

1. Write the balanced chemical equation.

Ratio:                   2 L                          1 L

         2Na₂O₂ + 2CO₂ → 2Na₂CO₃ + O₂

V/L:                    2.80

2. Calculate the volume of O₂.

According to Gay-Lussac, 1 L of O₂ forms from 2 L of CO₂.

Thus, the conversion factor is (1 L O₂/2 L CO₂).

Volume of CO₂ = 2.80 L CO₂ × (1 L O₂/1 L CO₂)

                         = 1.40 L O₂

1.40 L.

Explanation:

Na₂O₂ + CO₂ → Na₂CO₃ + 1/2 O₂

Where, P is the pressure of the gas in atm (P at STP = 1.0 atm).

V is the volume of the gas in L (V = 2.80 L).

R is the general gas constant (R = 0.082 L.atm/mol.K).

T is the temperature in K (T at STP = 0.0 °C + 273 = 273 K).

∴ n of CO₂ = PV / RT = (1.0 atm) (2.80 L) / (0.082 L.atm/mol.K) (273 K) = 2.80 / 22.386 = 0.125 mole.

From the stichiometry:

1.0 mole of CO₂ will produce → 0.50 mole of O₂

0.125 mole of CO₂ will produce → ??? mole of O₂

i just learnt this recently but i need to look through my notes again

im pretty sure its b