automotive air bags inflate when sodium azide rapidly decomposes as shown in this equation: 2nan3(s) → 2na(s) + 3n2(g) what mass of nan3 is necessary to produce 70.0 l of n2 gas at 315 k and 1.20 atm? 141 g nan3 422 g nan3 723 g nan3 948 g nan3

141.0 g NaN₃.

Explanation:

It is a stichiometric problem.

Firstly, we should wright the reaction as a balanced equation:

2NaN₃ → 2Na + 3N₂

It is clear that 2.0 moles of NaN₃ decompose to 2.0 mole of Na and 3.0 moles of N₂.

Then we should convert the volume of N₂ (70.0 L) to moles via using the gas law of ideal gas: PV = nRT, n = PV / RT,

Where, P is the pressure of the gas in atm (P = 1.2 atm).

V is the volume of the gas in L(V = 70.0 L).

R is the general gas constant (R = 0.082 L.atm/mol.K).

T is the temperature in K(T = 315 K).

∴ n of N₂ = PV / RT = (1.2 atm) (70.0 L) / (0.082 L.atm/mol.K) (315 K) = 3.252 mole.

From the stichiometry:

2.0 moles of NaN₃ decomposes to → 3.0 moles of N₂

??? mole of NaN₃ decomposes to → 3.2520 moles of N₂

The number of moles of NaN₃ = (2.0 moles of NaN₃) (3.2520 moles of N₂) / (3.0 moles of N₂) = 2.168 mole.

Finally, we can convert the number of moles of NaN₃ to mass using the relation: m = n x molar mass.

Molar mass of NaN₃ = 65.0 g/mol.

the mass of NaN₃ = n x molar mass = (2.168 mole) (65.0 g/mol) = 140.92 g ≅ 141.0 g.

conduction is the transfer of thermal energy (heat in transfer) due to collisions between the molecules in the object. collisions between adjacent atoms and molecules transfer kinetic energy from the warmer to the cooler object. the objects must be in physical contact.

level 4 to level 2 : ))