Chemistry, 27.01.2020 18:31 laura1649

What are 3 examples of ways that humans use this process to increase the value of a plant or animal for humans? (in other words, what are the three types of selective breeding? briefly describe each one

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Answer from: jrassicworld4ever

Answer 1 with Explanation

Selective breeding is a process used by humans for breeding plants and animal for obtaining some specific genetic traits. Simply, it involves breeding of such animals who have particular characteristics so that their offspring have more desirable features in them. The three main types of selective breedings are mentioned in the answers below.

Answer 2 (Example1)

Inbreeding

Explanation

It involves breeding of such animals or plants that are genetically similar to each other. A continued inbreeding results in offspring that are very genetically identical. Such breeding can cause genetic disorders. Because the offspring are very similar to their parents. Line breeding is a type of inbreeding when distant relatives are bred together.

Answer 3 (Example2)

Hybridization

Explanation

Hybridization occurs when two animals or plants having different species are bred together which results in offspring of desirable characteristics. This is common doing that is processed in this living era. As human have difference preferences. The offspring of them is known as a hybrid. Plants hybridize much more often than animals do.

Answer 4 (Example3)

Self Pollination:

Explanation

Some species of plants have both male and female reproductive parts, which leads to self-fertilization. This is a natural process by nature. They are capable of transferring the pollen from the anther to the stigma of the same flower or another flower on the same plant. Usually the process takes places through the flow of air. The pollen travels with the wind flow, landing on to the different plant.

Answer from: Quest

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 : $4x (s) + 3o_{2} (g) \rightarrow 2x_{2}o_{3} (s) h rxn = -600 kj/mol$

equation 2 : $2x (s) + 3cl_{2} (g) \rightarrow 2xcl_{3} (s) h rxn = -800 kj/mol$

equation 3 : $4xcl_{3} (s) + 3o_{2} (g) \rightarrow 2x_{2}o_{3} (s) + 6cl_(2} h rxn = -200 kj/mol$

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 : $4xcl_{3} (s) \rightarrow 4x (s) + 6cl_{2} ( h rxn = (+800) \times 2 kj/mol$

let us add equation 1 & 4

$4x (s) + 3o_{2} (g) \rightarrow 2x_{2}o_{3} (s) h rxn = -600 kj/mol$

$4xcl_{3} (s) \rightarrow 4x (s) + 6cl_{2} ( h rxn = (+1600) kj/mol$

$4xcl_{3} )s) + 3o_{2} \rightarrow 2x_{2}o_{3} (s) + 6cl_{2} (g) h rxn = (+1000) kj/mol$

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

Answer from: Quest

The law of conservation of mass states that a mass of an object or the amount of matter composed inside an object or thing will not change unless it is added or removed of the matter that is contained in the object itself.

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