Will give brainliest if 10g of sodium react with an unlimited amount of chlorine how much sodium chloride will get produced?

25.44g

Explanation:

Given parameters:

Mass of sodium = 10g

Mass of NaCl produced = ?

Solution

We first write the balanced reaction equation as shown below:

                                      2Na + Cl₂ → 2NaCl

From the information given about the reaction, we know that the chlorine gas is in excess. Sodium reactant is the limiting reagent. The amount of Na will determine the extent of the reaction and the amount of products that would be formed.

Now, we find the number of moles of Na that reacted and we can use the stoichiometeric relationship to determine the number of moles of the NaCl produced. This will then give us our unknown mass of NaCl

 Number of moles of Na =

                                         =  

                                         = 0.435moles

   From the equation of the reaction:

         2 moles of Na produced 2 moles of NaCl

        0.435 moles of Na will produce 0.435moles of NaCl

To find the mass of NaCl, we use the expression below:

             mass of NaCl = number of moles of NaCl x molar mass

Molar mass of NaCl = 23 + 35.5= 58.5g/mol

              mass of NaCl = 0.435 x 58.5 = 25.44g

m=9

step-by-step explanation: