Apump contains 0.5 l of air at 203kpa. you draw back on the piston of the pump until the pressure reads 25.4kpa. what is the volume of air in the pump?

a. 0.2l
b. 1.0l
c. 4.0l
d. 2.0l

= 4.0 L

Boyle's law states that the volume of a fixed mass of a gas is inversely proportional to pressure at a constant temperature.

Therefore; Volume α 1/pressure

Mathematically; V α 1/P

V = kP, where k is a constant;

P1V1 = P2V2

V1 = 0.5 l, P1 =203 kPa, P2 = 25.4 kPa

V2 = (0.5 × 203 )/25.4

    = 3.996

   ≈ 4.0 L

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