Agas has a pressure of 0.40 atm at 55.0 °c. what is the pressure at standard temperature?
show the formula and which law is it? !

0.33 atm.

By the Ideal Gas Law:

Where

.

under STP standard conditions.

,

.

The value of , , and shall be the same in the two equations.

Divide the second equation with the first:

.

.

Gay-Lussac's Law; p₁/T₁ = p₂/T₂; 0.33 atm

Step-by-step explanation:

The volume and number of moles are constant, so we can use Gay-Lussac’s Law:

At constant volume, the pressure exerted by a gas is directly proportional to its temperature.

p₁/T₁ = p₂/T₂     Invert each side of the equation

T₁/p₁ = T₂/p₂     Multiply each side by p₂

   T₂ = T₁ × p₁/p₂

    p₂ = p₁ × T₂/T₁

Data:

p₁ = 0.40 atm; T₁  = 55.0 °C

p₂ = ?;              T₂ =   0.0 °C

Calculations:

(a) Convert the temperatures to kelvins

T₁ = 55.0 + 273.15 = 328.15 K

T₂ =   0.0 + 273.15 = 273.15 K

(b) Calculate the new pressure

p₂ = 0.40 × 273.15/328.15

    = 0.40 × 0.832

    = 0.33 atm

The pressure drops to 0.33 atm.

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