[15 points, stoichiometry and gases]

find the grams of cac2 (@ 1.25 atm, 385 k and c2h2 has 550 l)

cac2 (s) + 2 h2o (l) > ca(oh)2 (s) + c2h2 (g)

The mass of calcium carbide is 1,392 grams.

Explanation:

Pressure of the ethyne gas = P = 1.25 atm

Volume of the ethyne gas = V = 550 L

Temperature of the ethyne gas = T = 385 K

Moles of ethyne gas = n

PV = nRT (ideal gas equation)

According to reaction , 1 mole of ethyne is obtained from 1 mole of calcium carbide.

Then 21.75 moles of ethyne will be obtained from:

calcium carbide.

Mass of 21.75 moles of calcium carbide:

= 21.75 mol × 64 g/mol = 1,392 g

The mass of calcium carbide is 1,392 grams.

la respuesta es si te gusta hacer lo que siempre haces cuando nunca ves a alguien en el espejo porque sabes que no siempre están ahí.

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.