What is the coefficient of silver in the final, balanced equation for this reaction?

3

Explanation:

An oxide-reduction reaction or, simply, redox reaction, is a chemical reaction in which one or more electrons are transferred between the reactants, causing a change in their oxidation states, which is the hypothetical electric charge that the atom would have if all its links with different elements were 100% ionic.

For there to be a reduction-oxidation reaction, in the system there must be an element that yields electrons and another that accepts them:

To balance a redox equation you must identify the elements that are oxidized and reduced and the amount of electrons that they release or capture, respectively.

In the reaction that arises in the question the silver (Ag) is reduced because it decreases its oxidation state from +1 to 0 and the aluminum (Al) is oxidized because its oxidation state increases from 0 to +3, releasing 3 electrons (e⁻). Then we can raise two half-reactions:

Ag⁺ + e⁻ → Ag⁰

Al⁰ → Al⁺³ + 3e⁻

In order to obtain the balanced equation, we must multiply the first half-reaction by 3 so that, when both half-reactions are added, the electrons are canceled. In this way:

(Ag⁺ + e⁻ → Ag⁰ ) x3

Al⁰ → Al⁺³ + 3e⁻               +

3Ag⁺ + Al⁰ → 3Ag⁰ + Al⁺³

So, the coefficient of silver in the final balanced equation is 3.

i do not get it   at all