Answers: 3
![[H^+]=6.3\times 10^{-11}](/tpl/images/0485/0260/7b92e.png)
and ![[OH^-]=1.58\times 10^{-4}](/tpl/images/0485/0260/a781b.png)
![pH=-\log [H^+]](/tpl/images/0485/0260/37e81.png)
![pOH=-log[OH^-]](/tpl/images/0485/0260/4fd6b.png)
![10.2=-\log [H^+]](/tpl/images/0485/0260/44045.png)
![3.8=-log[OH^-]](/tpl/images/0485/0260/49e4d.png)
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