When pcl5 solidifies it forms pcl4+ cations and pcl6– anions. according to valence bond theory,
m what hybrid orbitals are used by phosphorus in the pcl4+ cations?

a. sp
b. sp2
c. sp3
d. sp3d
e. sp3d2

Hey there!

No of hybrid orbitals , H = ( V +S - C + A ) / 2

Where H = no . of hybrid orbitals

V = Valence of the central atom = 5

S = No . of single valency atoms = 4

C = No . of cations = 1

A = No . of anions = 0

For PCl4 +

Plug the values we get H = ( 5+4-1+0) / 2

H =  4 ---> sp3 hybridization

sp3 hybrid orbitals are used by phosphorous in the PCl4+ cations

Answer C

Hope that helps!

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer