Caco3 + 2hcl --> cacl2 + co2 + h2o in the reaction above, what mass of carbon dioxide is produced when 10 moles of hcl reacts with excess calcium carbonate?

According to the stoichiometry the CO2 formed is 1/2 the moles of H2O. So take the moles of CO2 as 5moles.

n=m/M

Where :

n = mole

m = mass

M = molar mass

Molar mass of CO2 = 44gmol^-1

Therefore mass = 5mol× 44gmol^-1= 220g

Ifound this on google “these two compounds have a different ionic structure. caesium ion is larger in size when compared to the sodium ion. the charge gets more area to spread out evenly. so caesium chloride has a lower melting point than sodium chloride.” i hope this you for what your looking for

It’s b. mass i searched it up